Sunday , 29 September 2024

How to calculate Pi with Python

I am sure that many of you have wonder at least once in your live what is PI really? and how you can calculate it.

This is going to be a short post and i’ll try to keep it as simple as possible.

So first let’s begin explaining what pi actually is?

We can define Pi as a mathematical constant. It is defined as the ratio of a circle’s circumference to its diameter, but Pi it’s more than just that it’s turn out to be like i said before an mathematical constant and it appear in many different branches of math.

In this post i will teach you the one that i think is the easiest one.

we will begin knowing that π²/6 is equal to the sums of the inverse of all natural number power 2

this is the Basel problem prove by Euler in 1734. And its look kind of weird but trust me its really easy.

we can express it like this:

(1/1²)+(1/2²)+(1/3²)+(1/4²)+(1/5²)+(1/6²)+(1/7²)+(1/8²)+(1/9²)+…

thats and equal to somethis like 1.64493306684777…

So now we know that π²/6=1.64493306684777, so we can find out pi by clearing the equation and it’s end up like π²=(1.64493306684777)(6)

and that’s equal to 3.1415.

So now that we know how to calculate pi let’s code it.

So as you may notice it’s took the range from 1 to 1000000 that’s because it is and aproximation and we get closer to the actual real number of pi increasing the range of number to use.

I hope that you actually learned something in this post otherwise this is my first post and i will try to get better at it.

Note: 

Are you a content creator? If yes then we welcome bloggers & they can submit a guest post to our famous blog for free, just search in google, we are on top of search engine “ write for us + travel”, You will find “Lifeyet News”.

About Web Master

Check Also

C UM4K: THE FAST-RISING PROGRAMMING LANGUAGE WORTH LEARNING

Programming languages are the foundation of software development and power the technology we use every …

Leave a Reply

Your email address will not be published. Required fields are marked *